1 shapiro.test()方法
> x=c(0.051,0.926,0.209,0.358,1.672,-1.191,1.404,1.112,0.108,-0.429,0.746,1.304,0.292,-1.587,-0.815)
> shapiro.test(x)
Shapiro-Wilk normality test
data: x
W = 0.95991, p-value = 0.6908
说明：p-value = 0.6908>0.05，接受原假设，认为x服从正态分布。
2 QQ图检验
> x=c(0.051,0.926,0.209,0.358,1.672,-1.191,1.404,1.112,0.108,-0.429,0.746,1.304,0.292,-1.587,-0.815)
> qqnorm(w)
> qqline(w)
说明：散点图位于直线上，因而可以认为是正态分布。
